Component Z is connected directly across a 6.0 V d.c. power supply.
The graph below shows how the resistance of Component Z varies with light illuminance.
Which of these expressions gives the current, III (in amperes), in component Z when the illuminance is 50 lx50\text{ lx}50 lx?
I=6.02.0
I = \frac{6.0}{2.0}
I=2.06.0
I=6.0×2.0×103
I = 6.0 \times 2.0 \times 10^3
I=6.0×2.0×103
I=6.02.0×103
I = \frac{6.0}{2.0 \times 10^3}
I=2.0×1036.0
I=6.0×2.0
I = 6.0 \times 2.0
I=6.0×2.0