A deep-sea research probe is released from rest at the ocean surface and descends vertically. The probe is designed such that it experiences a constant downward acceleration of 3.2 m s−23.2\text{ m s}^{-2}3.2 m s−2 under the combined effects of gravity, buoyancy, and drag.
Calculate the final speed of the probe when it has descended a distance of 45 m45\text{ m}45 m. Give your answer to 2 significant figures.
Use the equation: v2−u2=2asv^2 - u^2 = 2asv2−u2=2as where: