Forces and motion

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Question 9
Easy

A flowerpot is knocked off a balcony and falls.

The initial velocity of the flowerpot is 0 m/s. The acceleration due to gravity is 9.8 m/s2.

Calculate the final velocity of the flowerpot when it has fallen a distance of 1.2 m through the air. Give your answer to 2 significant figures.

Use the equation:

v2−u2=2as v^2 - u^2 = 2as v2−u2=2as

where:

  • v v\,v is the final velocity
  • u u\,u is the initial velocity
  • a a\,a is the acceleration
  • s s\,s is the distance
[3]

Forces and motion Questions

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