A domestic appliance is connected to the mains electricity supply which has a potential difference of 240 V240\text{ V}240 V.
The current in the appliance is 0.15 A0.15\text{ A}0.15 A. Calculate the power of the appliance.
Use the equation:
power=potential difference×current \text{power} = \text{potential difference} \times \text{current} power=potential difference×currentCalculate the energy transferred by the appliance when 350 C350\text{ C}350 C of charge flows through it.
Use the equation:
energy transferred=charge flow×potential difference \text{energy transferred} = \text{charge flow} \times \text{potential difference} energy transferred=charge flow×potential differenceThe appliance has a fault containing an exposed live wire. Describe the difference between the hazard and the risk in this scenario for someone repairing the appliance.
9 exam-style questions on AQA GCSE Physics 2.3 Domestic uses and safety, covering 2.3.1 Direct and alternating potential difference and 2.3.2 Mains electricity. Each one has a worked solution and a mark scheme showing where the marks go.