A curve has the equation x3−x2y−y+1=0x^3 - x^2y - y + 1 = 0x3−x2y−y+1=0
Show that dydx=3x2−2xyx2+1\displaystyle \frac{dy}{dx} = \frac{3x^2 - 2xy}{x^2 + 1}dxdy=x2+13x2−2xy
Find the equation of the normal to the curve at the point (1, 1).
717 exam-style questions on Edexcel A Level Maths Differentiation, covering 9.1 Differentiating sin x and cos x, 9.2 Differentiating exponentials and logarithms, 9.3 The Chain Rule, 9.4 The Product Rule, 9.5 The Quotient Rule, 9.6 Differentiating Trigonometric Functions, 9.7 Parametric Differentiation, 9.8 Implicit Differentiation, 9.9 Using Second Derivatives, and 9.10 Rates of Change. Each one has a worked solution and a mark scheme showing where the marks go.