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Differentiation

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Question 27
y=x2+6x(x+3)2x≠−3 y = \frac{x^2 + 6x}{(x + 3)^2} \quad x \neq -3 y=(x+3)2x2+6x​x=−3
a.

Show that dydx=A(x+3)n\displaystyle \frac{dy}{dx} = \frac{A}{(x + 3)^n}dxdy​=(x+3)nA​ where A A\,A and n n\,n are constants to be found.

[4]
b.

Hence deduce the range of values for x x\,x for which dydx<0\displaystyle \frac{dy}{dx} < 0dxdy​<0

[1]
Markscheme

Differentiation Questions

  1. A Level
  2. /Maths
  3. /Differentiation

711 exam-style questions on Edexcel A Level Maths Differentiation, covering 9.1 Differentiating sin x and cos x, 9.2 Differentiating exponentials and logarithms, 9.3 The Chain Rule, 9.4 The Product Rule, 9.5 The Quotient Rule, 9.6 Differentiating Trigonometric Functions, 9.7 Parametric Differentiation, 9.8 Implicit Differentiation, 9.9 Using Second Derivatives, and 9.10 Rates of Change. Each one has a worked solution and a mark scheme showing where the marks go.

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