Using xn+1=2+3xn\displaystyle x_{n+1} = 2 + \frac{3}{x_n}xn+1=2+xn3 with x0=1x_0 = 1x0=1
Find the values of x1x_1x1, x2 x_2\,x2 and x3x_3x3.
Explain the relationship between the values of x1x_1x1, x2 x_2\,x2 and x3 x_3\,x3 and the equation x2−2x−3=0x^2 - 2x - 3 = 0x2−2x−3=0
