Skip to content
MathsGenie logo
Open app

Course home

  1. GCSE
  2. Maths WJEC
  3. Question bank

Iteration

EasyMediumHard
1234567
Question 7

Using xn+1=5xn2+3\displaystyle x_{n+1} = \frac{5}{x_n^2 + 3}xn+1​=xn2​+35​ with x0=1x_0 = 1x0​=1

Find the values of x1x_1x1​, x2 x_2\,x2​ and x3x_3x3​.

[3]

Iteration Questions

  1. GCSE
  2. /Maths
  3. /Iteration