Iteration

Using $xn+1=15xn2+4\displaystyle x_{n+1} = \frac{15}{x_n^2 + 4}$ with $x_0 = 1$

Find the values of $x_1$ , $x_2\,$ and $x_3$ .

[3]

Using $xn+1=15xn2+4\displaystyle x_{n+1} = \frac{15}{x_n^2 + 4}$ with $x_0 = 1$

Find the values of $x_1$ , $x_2\,$ and $x_3$ .

[3]

Iteration Questions