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Iteration

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Question 2

Using xn+1=xn+153x_{n+1} = \sqrt[3]{x_n + 15}xn+1​=3xn​+15​ with x0=3x_0 = 3x0​=3

Find the values of x1x_1x1​, x2 x_2\,x2​ and x3x_3x3​.

[3]

Iteration Questions

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