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Iteration

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Question 1
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Using xn+1=6xn+2\displaystyle x_{n+1} = \frac{6}{x_n + 2}xn+1​=xn​+26​ with x0=2x_0 = 2x0​=2

Find the values of x1x_1x1​, x2 x_2\,x2​ and x3x_3x3​.

[3]

Iteration Questions

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