Using xn+1=5xn2+2\displaystyle x_{n+1} = \frac{5}{x_n^2} + 2xn+1=xn25+2 with x0=2.5x_0 = 2.5x0=2.5
Find the values of x1x_1x1, x2 x_2\,x2 and x3x_3x3.
Explain the relationship between the values of x1x_1x1, x2 x_2\,x2 and x3 x_3\,x3 and the equation x3−2x2−5=0x^3 - 2x^2 - 5 = 0x3−2x2−5=0
