Using xn+1=6xn2+2\displaystyle x_{n+1} = \frac{6}{x_n^2} + 2xn+1=xn26+2 with x0=2x_0 = 2x0=2
Find the values of x1x_1x1, x2 x_2\,x2 and x3x_3x3.
Explain the relationship between the values of x1x_1x1, x2 x_2\,x2 and x3 x_3\,x3 and the equation x3−2x2−6=0x^3 - 2x^2 - 6 = 0x3−2x2−6=0
