A student dissolves 2.65 g of sodium carbonate in water and makes the solution up to 250 cm3\mathrm{cm^{3}}cm3.
The student then takes 25.0 cm3\mathrm{cm^{3}}cm3 of this solution and adds water until the total volume is 100 cm3\mathrm{cm^{3}}cm3.
Relative formula mass (MrM_rMr): Na2CO3\mathrm{Na_{2}CO_{3}}Na2CO3 = 106.0
What is the concentration of the diluted solution?
0.00250 mol/dm3\mathrm{mol/dm^{3}}mol/dm3
0.0250 mol/dm3\mathrm{mol/dm^{3}}mol/dm3
0.100 mol/dm3\mathrm{mol/dm^{3}}mol/dm3
0.400 mol/dm3\mathrm{mol/dm^{3}}mol/dm3
57 exam-style questions on OCR GCSE Chemistry 5.1 Monitoring chemical reactions, covering 5.1.1 The technique of titration, 5.1.2 Theoretical mass, percentage yield and atom economy, 5.1.3 Concentration of a solution in mol/dm3, 5.1.4 Concentration calculations and titration results, 5.1.5 Molar gas volume and volumes of gases in reactions, and 5.1.6 Choosing a reaction pathway. Each one has a worked solution and a mark scheme showing where the marks go.