A container holds 250 cm3\mathrm{cm^{3}}cm3 of calcium chloride solution. The solution contains 4.44 g of calcium chloride, CaCl2\mathrm{CaCl_{2}}CaCl2.
A laboratory needs 500 cm3\mathrm{cm^{3}}cm3 of calcium chloride solution with a concentration of 0.0400 mol/dm3\mathrm{mol/dm^{3}}mol/dm3. A volume of the solution from the container is measured and diluted with water to make 500 cm3\mathrm{cm^{3}}cm3.
Relative formula mass (MrM_rMr): CaCl2\mathrm{CaCl_{2}}CaCl2 = 111.0
What is the volume of solution that must be measured from the container?
125 cm3\mathrm{cm^{3}}cm3
62.5 cm3\mathrm{cm^{3}}cm3
375 cm3\mathrm{cm^{3}}cm3
250 cm3\mathrm{cm^{3}}cm3
152 exam-style questions on OCR GCSE Chemistry 5.1 Monitoring chemical reactions, covering 5.1.1 The technique of titration, 5.1.2 Theoretical mass, percentage yield and atom economy, 5.1.3 Concentration of a solution in mol/dm3, 5.1.4 Concentration calculations and titration results, 5.1.5 Molar gas volume and volumes of gases in reactions, and 5.1.6 Choosing a reaction pathway. Each one has a worked solution and a mark scheme showing where the marks go.