Lead(II) nitrate decomposes into lead(II) oxide, nitrogen dioxide, and oxygen according to the following balanced equation:
2Pb(NO3)2→2PbO+4NO2+O2 2\text{Pb}(\text{NO}_3)_2 \rightarrow 2\text{PbO} + 4\text{NO}_2 + \text{O}_2 2Pb(NO3)2→2PbO+4NO2+O2How many moles of products are formed if 12 mol of lead(II) nitrate decomposes?
12 mol12\text{ mol}12 mol of PbO\text{PbO}PbO, 12 mol12\text{ mol}12 mol of NO2\text{NO}_2NO2, 12 mol12\text{ mol}12 mol of O2\text{O}_2O2
12 mol12\text{ mol}12 mol of PbO\text{PbO}PbO, 24 mol24\text{ mol}24 mol of NO2\text{NO}_2NO2, 6 mol6\text{ mol}6 mol of O2\text{O}_2O2
24 mol24\text{ mol}24 mol of PbO\text{PbO}PbO, 12 mol12\text{ mol}12 mol of NO2\text{NO}_2NO2, 6 mol6\text{ mol}6 mol of O2\text{O}_2O2
24 mol24\text{ mol}24 mol of PbO\text{PbO}PbO, 24 mol24\text{ mol}24 mol of NO2\text{NO}_2NO2, 12 mol12\text{ mol}12 mol of O2\text{O}_2O2
91 exam-style questions on OCR GCSE Chemistry Monitoring chemical reactions. Each one has a worked solution and a mark scheme showing where the marks go.