During industrial monitoring of the contact process, a chemical engineer determines that 64.0 g of sulfur dioxide reacts completely with 16.0 g of oxygen to yield 80.0 g of sulfur trioxide:
2SO2(g)+O2(g)→2SO3(g) 2\text{SO}_2(g) + \text{O}_2(g) \rightarrow 2\text{SO}_3(g) 2SO2(g)+O2(g)→2SO3(g)How much oxygen is required to produce 600.0 g of sulfur trioxide under the same reaction conditions?
96.0 g96.0\text{ g}96.0 g
480.0 g480.0\text{ g}480.0 g
160.0 g160.0\text{ g}160.0 g
120.0 g120.0\text{ g}120.0 g
91 exam-style questions on OCR GCSE Chemistry Monitoring chemical reactions. Each one has a worked solution and a mark scheme showing where the marks go.