During a monitoring experiment, a student reacts 2.08 g of barium chloride (BaCl2\text{BaCl}_2BaCl2) with excess sodium sulfate (Na2SO4\text{Na}_2\text{SO}_4Na2SO4) to produce 2.33 g of barium sulfate (BaSO4\text{BaSO}_4BaSO4) precipitate according to the chemical equation:
BaCl2(aq)+Na2SO4(aq)→BaSO4(s)+2NaCl(aq) \text{BaCl}_2(\text{aq}) + \text{Na}_2\text{SO}_4(\text{aq}) \rightarrow \text{BaSO}_4(\text{s}) + 2\text{NaCl}(\text{aq}) BaCl2(aq)+Na2SO4(aq)→BaSO4(s)+2NaCl(aq)How much barium sulfate precipitate will be formed if the student repeats the reaction under identical conditions starting with 0.0520 g of barium chloride?
0.0464 g0.0464\text{ g}0.0464 g
0.0583 g0.0583\text{ g}0.0583 g
0.121 g0.121\text{ g}0.121 g
0.583 g0.583\text{ g}0.583 g