A chemist reacts 6.0 g of hydrogen with excess nitrogen to make ammonia.
N2+3H2⇌2NH3 \mathrm{N_{2} + 3H_{2} \rightleftharpoons 2NH_{3}} N2+3H2⇌2NH3The chemist collects 20.4 g of ammonia.
Relative atomic mass (ArA_rAr): H = 1.0 N = 14.0
What is the percentage yield of ammonia?
29.4%
30.0%
40.0%
60.0%
57 exam-style questions on OCR GCSE Chemistry 5.1 Monitoring chemical reactions, covering 5.1.1 The technique of titration, 5.1.2 Theoretical mass, percentage yield and atom economy, 5.1.3 Concentration of a solution in mol/dm3, 5.1.4 Concentration calculations and titration results, 5.1.5 Molar gas volume and volumes of gases in reactions, and 5.1.6 Choosing a reaction pathway. Each one has a worked solution and a mark scheme showing where the marks go.