Averages GCSE Maths: Every Question Type
Averages GCSE maths made clear: learn mean, median, mode and range from lists and frequency tables, then compare data confidently in your resit.

Averages can look like a safe part of the paper. Then the data is unordered, a frequency table appears, or the question asks you to compare two groups. A familiar calculation suddenly feels less certain.
The good news is that averages GCSE maths questions follow a small set of dependable methods. You need to understand what each measure tells you, recognise how the data is presented and show enough working to secure the marks. This guide covers mean, median, mode and range, including frequency tables, grouped data, missing values and comparisons.
The averages checklist
Before calculating, identify exactly what the question wants.
- Mean: add the values and divide by how many there are.
- Median: order the values and find the middle.
- Mode: identify the value occurring most often.
- Range: subtract the smallest value from the largest.
- Frequency table: account for how often each value occurs.
- Comparison: discuss a typical value and the spread.
If these methods are not yet automatic, start with the free Averages revision lesson.
Mean, median, mode and range from a list
Consider the number of questions completed in six revision sessions:
7, 4, 9, 6, 4, 12 7,\ 4,\ 9,\ 6,\ 4,\ 12 7, 4, 9, 6, 4, 12Finding the mean
The mean is the total divided by the number of values.
Mean=7+4+9+6+4+126=426=7 \text{Mean}=\frac{7+4+9+6+4+12}{6}=\frac{42}{6}=7 Mean=67+4+9+6+4+12=642=7Write the division explicitly. A correct total on a calculator does not always communicate the complete method.
Finding the median
First place the data in ascending order:
4, 4, 6, 7, 9, 12 4,\ 4,\ 6,\ 7,\ 9,\ 12 4, 4, 6, 7, 9, 12There are six values, so use the third and fourth values:
Median=6+72=6.5 \text{Median}=\frac{6+7}{2}=6.5 Median=26+7=6.5With an odd number of values, select the single middle value. With an even number, calculate the mean of the two middle values.
Finding the mode and range
The value 444 appears most often, so:
Mode=4 \text{Mode}=4 Mode=4The range measures spread rather than what is typical:
Range=12−4=8 \text{Range}=12-4=8 Range=12−4=8A data set can have two modes or no mode. For the range, use only the largest and smallest values.
Finding averages from a frequency table
A frequency table records how often each value occurs.
| Correct answers, xxx | Frequency, fff | fxfxfx |
|---|---|---|
| 222 | 111 | 222 |
| 333 | 444 | 121212 |
| 444 | 333 | 121212 |
| 555 | 222 | 101010 |
| Total | 101010 | 363636 |
Multiply each value by its frequency, add the products and divide by the total frequency:
Mean=∑fx∑f=3610=3.6 \text{Mean}=\frac{\sum fx}{\sum f}=\frac{36}{10}=3.6 Mean=∑f∑fx=1036=3.6The frequency tells you how many copies of each value are in the data set. The fxfxfx column records their contribution to the total.
There are 101010 results, so the median lies halfway between the fifth and sixth values. Positions 222-555 have value 333, while positions 666-888 have value 444. Therefore:
Median=3+42=3.5 \text{Median}=\frac{3+4}{2}=3.5 Median=23+4=3.5The highest frequency is 444, belonging to the value 333, so the mode is 333. The range is:
5−2=3 5-2=3 5−2=3Read the mode from the value column, not the frequency column. Build confidence with the Averages from Frequency Tables lesson and its frequency-table revision guide.
Estimated mean from grouped data
Grouped tables contain intervals rather than exact observations, so the mean can only be estimated.
| Time, ttt minutes | Frequency, fff | Midpoint, xxx | fxfxfx |
|---|---|---|---|
| 0<t≤100<t\leq100<t≤10 | 333 | 555 | 151515 |
| 10<t≤2010<t\leq2010<t≤20 | 555 | 151515 | 757575 |
| 20<t≤3020<t\leq3020<t≤30 | 222 | 252525 | 505050 |
| Total | 101010 | 140140140 |
Use each interval midpoint as a representative value. For example:
10+202=15 \frac{10+20}{2}=15 210+20=15Then calculate:
Estimated mean=14010=14 \text{Estimated mean}=\frac{140}{10}=14 Estimated mean=10140=14The word estimated matters. The five observations in the second interval are not necessarily all 151515 minutes. Their exact values are unknown, so the midpoint is an assumption.
Reverse mean questions
When the mean is given and one value is missing, find the required total first.
Five scores have a mean of 121212. Four scores are 888, 111111, 141414 and 161616.
Required total=12×5=60 \text{Required total}=12\times5=60 Required total=12×5=60 Known total=8+11+14+16=49 \text{Known total}=8+11+14+16=49 Known total=8+11+14+16=49 Missing score=60−49=11 \text{Missing score}=60-49=11 Missing score=60−49=11The useful relationship is:
Total=Mean×Number of values \text{Total}=\text{Mean}\times\text{Number of values} Total=Mean×Number of valuesComparing two distributions
A strong comparison interprets the calculations. Suppose Group A has a median of 181818 and a range of 777, while Group B has a median of 151515 and a range of 121212.
Group A generally scored higher because its median was larger. Its results were also more consistent because its range was smaller. This compares both location and spread, quotes the figures and refers to the groups.
Avoid unsupported statements such as “A is better”. Later topics extend this reasoning through the Cumulative Frequency revision resources and Box Plots lesson.
Choosing the most suitable average
The mean uses every value, but an extreme value can affect it strongly. The median is often more representative for skewed data or data containing outliers. The mode is useful when the most common value or category matters. The range is not an average; it describes spread.
For salaries of £22,000£22{,}000£22,000, £24,000£24{,}000£24,000, £25,000£25{,}000£25,000, £27,000£27{,}000£27,000 and £150,000£150{,}000£150,000, the unusually high salary pulls the mean upwards. The median may better represent a typical salary. In an explanation question, state why your chosen average suits the data.
Common mistakes that lose marks
- Not ordering data: the median is the middle value only after ordering.
- Dividing by the wrong number: in a frequency table, divide by the total frequency, not the number of rows.
- Confusing value and frequency: the largest frequency identifies the modal value.
- Calling the range an average: it measures spread using the largest and smallest values.
- Treating grouped data as exact: a calculation using class midpoints gives an estimate.
- Comparing one feature only: compare a mean or median and a measure of spread.
Turn the method into reliable marks
Progress often comes from making ordinary methods dependable. Learn one question type, practise it without notes, mark it honestly and revisit any error later. This reveals where marks are being lost more clearly than rushing through question after question.
Use the GCSE Maths revision hub for lessons and practice questions, then move to the GCSE papers collection for mini tests, predicted papers, past papers and mark schemes. Add weaker topics to your revision planner and use video solutions to understand each method.
Mean, median, mode and range are not disconnected rules. Together, they describe what is typical and how much the data varies. Once you recognise the structure of each question, averages can become a reliable source of GCSE marks.



