Given that u=1+cosxu = 1 + \cos xu=1+cosx, find dudx\displaystyle \frac{du}{dx}dxdu and the corresponding limits.
Hence use the substitution u=1+cosxu = 1 + \cos xu=1+cosx to find ∫0π2sinx1+cosxdx\displaystyle \int_0^{\frac{\pi}{2}} \frac{\sin x}{1 + \cos x} dx∫02π1+cosxsinxdx
864 exam-style questions on Edexcel A Level Maths Integration, covering 11.1 Integrating Standard Functions, 11.2 Integrating f(ax + b), 11.3 Using Trigonometric Identities, 11.4 Reverse Chain Rule, 11.5 Integration by Substitution, 11.6 Integration by Parts, 11.7 Partial Fractions, 11.8 Finding Areas, 11.9 The Trapezium Rule, 11.10 Solving Differential Equations, and 11.11 Modelling with Differential Equations. Each one has a worked solution and a mark scheme showing where the marks go.