The curve C has the parametric equations
x=ln(t+4)y=1t+3t>−3 x = \ln(t+4) \quad y = \frac{1}{t+3} \quad t > -3 x=ln(t+4)y=t+31t>−3The finite region R between by the curve C and the x x\,x axis is bounded by the the lines with equations x=ln4x = \ln 4x=ln4 and x=ln8x = \ln 8x=ln8
Show that the area of R is given by the integral ∫041(t+3)(t+4) dt\displaystyle \int_0^4 \frac{1}{(t+3)(t+4)}\,dt∫04(t+3)(t+4)1dt
Hence find an exact value for this area
864 exam-style questions on Edexcel A Level Maths Integration, covering 11.1 Integrating Standard Functions, 11.2 Integrating f(ax + b), 11.3 Using Trigonometric Identities, 11.4 Reverse Chain Rule, 11.5 Integration by Substitution, 11.6 Integration by Parts, 11.7 Partial Fractions, 11.8 Finding Areas, 11.9 The Trapezium Rule, 11.10 Solving Differential Equations, and 11.11 Modelling with Differential Equations. Each one has a worked solution and a mark scheme showing where the marks go.