Express sin2x \sin^2 x\,sin2x in terms of cos2x\cos 2xcos2x
Hence show that
∫sin2x dx=∫(12−12cos2x) dx \int \sin^2 x \, dx = \int \left(\frac{1}{2} - \frac{1}{2} \cos 2x\right) \, dx ∫sin2xdx=∫(21−21cos2x)dxFind: ∫sin2x dx\int \sin^2 x \, dx∫sin2xdx
864 exam-style questions on Edexcel A Level Maths Integration, covering 11.1 Integrating Standard Functions, 11.2 Integrating f(ax + b), 11.3 Using Trigonometric Identities, 11.4 Reverse Chain Rule, 11.5 Integration by Substitution, 11.6 Integration by Parts, 11.7 Partial Fractions, 11.8 Finding Areas, 11.9 The Trapezium Rule, 11.10 Solving Differential Equations, and 11.11 Modelling with Differential Equations. Each one has a worked solution and a mark scheme showing where the marks go.