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Question 156

The region R R\,R which is bounded by the curve with equation y=16(2x+1)y = \sqrt{16(2^x + 1)}y=16(2x+1)​, the xxx-axis and the lines x=0x = 0x=0 and x=3x = 3x=3.

An unnumbered coordinate diagram shows an increasing curve, axes labelled x and y, origin O, a vertical boundary and region R.

a.

Complete the table below, giving values of 16(2x+1) \sqrt{16(2^x + 1)}\,16(2x+1)​ to 3 decimal places.

xxx00.511.522.53
16(2x+1)\sqrt{16(2^x + 1)}16(2x+1)​5.6576.2156.9287.827
[2]
b.

Use the trapezium rule to find an approximation for the area of RRR.

[4]
c.

State, giving a reason, whether your approximation in part (b) is an overestimate or an underestimate for the area of RRR.

[2]
Markscheme

Integration Questions

  1. A Level
  2. /Maths
  3. /Integration

864 exam-style questions on Edexcel A Level Maths Integration, covering 11.1 Integrating Standard Functions, 11.2 Integrating f(ax + b), 11.3 Using Trigonometric Identities, 11.4 Reverse Chain Rule, 11.5 Integration by Substitution, 11.6 Integration by Parts, 11.7 Partial Fractions, 11.8 Finding Areas, 11.9 The Trapezium Rule, 11.10 Solving Differential Equations, and 11.11 Modelling with Differential Equations. Each one has a worked solution and a mark scheme showing where the marks go.

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