Use the substitution u=1+2cosxu = 1 + 2\cos xu=1+2cosx to find ∫0π22sinx1+2cosxdx\displaystyle \int_0^{\frac{\pi}{2}} \frac{2\sin x}{1 + 2\cos x} dx∫02π1+2cosx2sinxdx
864 exam-style questions on Edexcel A Level Maths Integration, covering 11.1 Integrating Standard Functions, 11.2 Integrating f(ax + b), 11.3 Using Trigonometric Identities, 11.4 Reverse Chain Rule, 11.5 Integration by Substitution, 11.6 Integration by Parts, 11.7 Partial Fractions, 11.8 Finding Areas, 11.9 The Trapezium Rule, 11.10 Solving Differential Equations, and 11.11 Modelling with Differential Equations. Each one has a worked solution and a mark scheme showing where the marks go.