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Further Kinematics

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Question 9

A ship S S\,S moves with a constant velocity. At 11:00, S S\,S is at the point with position vector (−4i+5j) km(-4\mathbf{i} + 5\mathbf{j}) \text{ km}(−4i+5j) km with respect to a fixed origin OOO. At 13:00, the ship is at the point with position vector (8i−1j) km(8\mathbf{i} - 1\mathbf{j}) \text{ km}(8i−1j) km.

a.

Find the velocity of SSS.

[2]
b.

Find the bearing of the velocity vector.

[2]
c.

Find an expression, in terms of ttt, for the position of SSS t t\,t hours after 11:00.

[2]
Markscheme

Further Kinematics Questions

  1. A Level
  2. /Maths
  3. /Further Kinematics

363 exam-style questions on Edexcel A Level Maths Further Kinematics, covering 8.1 Vectors in Kinematics, 8.2 Vector Methods with Projectiles, 8.3 Variable Acceleration in One Dimension, 8.4 Differentiating Vectors, and 8.5 Integrating Vectors. Each one has a worked solution and a mark scheme showing where the marks go.

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