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Further Kinematics

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Question 53

A particle P P\,P moves with constant acceleration 3i−2j3\mathbf{i} - 2\mathbf{j}3i−2j ms−2^{-2}−2. When t=0t = 0t=0, the particle is at point A A\,A and moving with a velocity −5i+5j-5\mathbf{i} + 5\mathbf{j}−5i+5j ms−1^{-1}−1. At time t=Tt = Tt=T the particle is moving in the direction of vector (−2i+3j)(-2\mathbf{i} + 3\mathbf{j})(−2i+3j)

Find the value of TTT.

[4]
Markscheme

Further Kinematics Questions

  1. A Level
  2. /Maths
  3. /Further Kinematics

363 exam-style questions on Edexcel A Level Maths Further Kinematics, covering 8.1 Vectors in Kinematics, 8.2 Vector Methods with Projectiles, 8.3 Variable Acceleration in One Dimension, 8.4 Differentiating Vectors, and 8.5 Integrating Vectors. Each one has a worked solution and a mark scheme showing where the marks go.

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