A particle P P\,P moves with constant acceleration (3i−4j) ms−2(3\mathbf{i} - 4\mathbf{j}) \text{ ms}^{-2}(3i−4j) ms−2. At time t=0t = 0t=0, P P\,P has speed u ms−1u \text{ ms}^{-1}u ms−1. At time t=2 st = 2 \text{ s}t=2 s, P P\,P has velocity (11i+4j) ms−1(11\mathbf{i} + 4\mathbf{j}) \text{ ms}^{-1}(11i+4j) ms−1.
Show that the velocity of P P\,P at time t=0t = 0t=0 is (5i+12j) ms−1(5\mathbf{i} + 12\mathbf{j}) \text{ ms}^{-1}(5i+12j) ms−1.
Find the value of uuu.
363 exam-style questions on Edexcel A Level Maths Further Kinematics, covering 8.1 Vectors in Kinematics, 8.2 Vector Methods with Projectiles, 8.3 Variable Acceleration in One Dimension, 8.4 Differentiating Vectors, and 8.5 Integrating Vectors. Each one has a worked solution and a mark scheme showing where the marks go.