At time t t\,t seconds, where t≥0t \geq 0t≥0, a particle P P\,P moves so that its acceleration a ms−2\mathbf{a} \text{ ms}^{-2}a ms−2 is given by a=(2−2t)i+(6−t2)j\mathbf{a} = (2 - 2t)\mathbf{i} + (6 - t^2)\mathbf{j}a=(2−2t)i+(6−t2)j. At the instant when t=0t = 0t=0, the velocity of P P\,P is 17i ms−117\mathbf{i} \text{ ms}^{-1}17i ms−1
Find the velocity of P P\,P when t=4t = 4t=4
363 exam-style questions on Edexcel A Level Maths Further Kinematics, covering 8.1 Vectors in Kinematics, 8.2 Vector Methods with Projectiles, 8.3 Variable Acceleration in One Dimension, 8.4 Differentiating Vectors, and 8.5 Integrating Vectors. Each one has a worked solution and a mark scheme showing where the marks go.