Skip to content

Course home

Further Kinematics

Further Kinematics

EasyMediumHard
123456789101112131415161718192021222324252627282930313233343536373839404142434445464748495051525354555657585960616263646566676869707172737475767778798081828384858687888990919293949596979899100101102103104105106107108109110111112113114115116117118119120121122123124125126127128129130131132133134135136137138139140141142143144145146147148149150151152153154155156157158159160161162163164165166167168169170171172173174175176177178179180181182183184185186187188189190191192193194195196197198199200201202203204205206207208209210211212213214215216217218219220221222223224225226227228229230231232233234235236237238239240241242243244245246247248249250251252253254255256257258259260261262263264265266267268269270271272273274275276277278279280281282283284285286287288289290291292293294295296297298299300301302303304305306307308309310311312313314315316317318319320321322323324325326327328
Question 246

After t t\,t seconds, a particle P P\,P has position vector r=[(t2+5t−2)i+(t3+2t2)j] m\mathbf{r} = [(t^2 + 5t - 2)\mathbf{i} + (t^3 + 2t^2)\mathbf{j}] \text{ m}r=[(t2+5t−2)i+(t3+2t2)j] m

a.

Given that the displacement of P P\,P is 12i+16j m12\mathbf{i} + 16\mathbf{j} \text{ m}12i+16j m, find the value of ttt

[2]
b.

Given that the velocity of P P\,P is 11i+39j ms−111\mathbf{i} + 39\mathbf{j} \text{ ms}^{-1}11i+39j ms−1, find the value of ttt

[3]
Markscheme

Further Kinematics Questions

  1. A Level
  2. /Maths
  3. /Further Kinematics

363 exam-style questions on Edexcel A Level Maths Further Kinematics, covering 8.1 Vectors in Kinematics, 8.2 Vector Methods with Projectiles, 8.3 Variable Acceleration in One Dimension, 8.4 Differentiating Vectors, and 8.5 Integrating Vectors. Each one has a worked solution and a mark scheme showing where the marks go.

Question bank