A particle P P\,P moves in a straight line with constant velocity. Initially P P\,P is at the point A A\,A with position vector (4i−3j) m(4\mathbf{i} - 3\mathbf{j}) \text{ m}(4i−3j) m. The velocity of P P\,P is (−6i+8j) m s−1(-6\mathbf{i} + 8\mathbf{j}) \text{ m s}^{-1}(−6i+8j) m s−1.
At time t=3t = 3t=3, P P\,P is at the point BBB. Find the position vector of BBB.
When t=5t = 5t=5 P P\,P is at the point CCC. Find the distance ACACAC.
363 exam-style questions on Edexcel A Level Maths Further Kinematics, covering 8.1 Vectors in Kinematics, 8.2 Vector Methods with Projectiles, 8.3 Variable Acceleration in One Dimension, 8.4 Differentiating Vectors, and 8.5 Integrating Vectors. Each one has a worked solution and a mark scheme showing where the marks go.