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Further Kinematics

Further Kinematics

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Question 147

After t t\,t seconds, a particle P P\,P has position vector r=[(t3+2t+3)i+(t2+2t−1)j] m\mathbf{r} = [(t^3 + 2t + 3)\mathbf{i} + (t^2 + 2t - 1)\mathbf{j}] \text{ m}r=[(t3+2t+3)i+(t2+2t−1)j] m

a.

Find an expression for the velocity of P P\,P in terms of ttt

[2]
b.

Find an expression for the acceleration of P P\,P in terms of ttt

[2]
Markscheme

Further Kinematics Questions

  1. A Level
  2. /Maths
  3. /Further Kinematics

326 exam-style questions on Edexcel A Level Maths Further Kinematics, covering 8.1 Vectors in Kinematics, 8.2 Vector Methods with Projectiles, 8.3 Variable Acceleration in One Dimension, 8.4 Differentiating Vectors, and 8.5 Integrating Vectors. Each one has a worked solution and a mark scheme showing where the marks go.

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