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1 Pure Mathematics

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Question 124

a=−5i+7j+2k\mathbf{a} = -5\mathbf{i} + 7\mathbf{j} + 2\mathbf{k}a=−5i+7j+2k and b=xi+yj+zk\mathbf{b} = x\mathbf{i} + y\mathbf{j} + z\mathbf{k}b=xi+yj+zk

Given that the resultant force of a\mathbf{a}a and b\mathbf{b}b is −2i−3j+6k-2\mathbf{i} - 3\mathbf{j} + 6\mathbf{k}−2i−3j+6k find the values of xxx, y y\,y and zzz

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1 Pure Mathematics Questions

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