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1 Pure Mathematics

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Question 78
a.

Express 1(1+2x)(1−x)\frac{1}{(1+2x)(1-x)}(1+2x)(1−x)1​ in partial fractions.

[3]
b.

Hence find the solution of the differential equation

(1+2x)(1−x)dydx=tan⁡y (1+2x)(1-x)\frac{dy}{dx} = \tan y (1+2x)(1−x)dxdy​=tany

for the interval −12<x<1-\frac{1}{2} < x < 1−21​<x<1, given that y=π2y = \frac{\pi}{2}y=2π​ when x=0x = 0x=0.

Give your answer in the form sin⁡ny=f(x)\sin^n y = f(x)sinny=f(x) where nnn is an integer to be found.

[7]

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