By writing cos3θ \cos 3\theta\,cos3θ as cos(2θ+θ)\cos(2\theta + \theta)cos(2θ+θ), show that
cos3θ≡4cos3θ−3cosθ\cos 3\theta \equiv 4\cos^3\theta - 3\cos\thetacos3θ≡4cos3θ−3cosθ
Solve, for 0≤θ≤π0 \leq \theta \leq \pi0≤θ≤π, the equation
4cos3θ−3cosθ=0.54\cos^3\theta - 3\cos\theta = 0.54cos3θ−3cosθ=0.5
Give your answers in terms of π\piπ.