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1 Pure Mathematics

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Question 645

Given that θ \theta\,θ is small and is measured in radians, use the small angle approximations to find an approximate value of

4θsin⁡3θ1−cos⁡2θ\displaystyle \frac{4\theta \sin 3\theta}{1 - \cos 2\theta}1−cos2θ4θsin3θ​

[3]
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1 Pure Mathematics Questions

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