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Question 193

A precision thermal probe uses a linear scaling function HHH to map a raw voltage vvv to a temperature reading H(v)H(v)H(v), defined by:

H(v)=11v−214 H(v) = \frac{11v - 21}{4} H(v)=411v−21​

A technician identifies a specific voltage where the probe's output is identical to the output of the inverse scaling function H−1H^{-1}H−1 applied to that same voltage.

Solve the equation:

H(v)=H−1(v) H(v) = H^{-1}(v) H(v)=H−1(v)

Select your answer from the options below:

v=−3v = -3v=−3

v=1v = 1v=1

v=3v = 3v=3

v=7v = 7v=7

[2]

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