It is given that x=3+5x = 3 + \sqrt{5}x=3+5.
Show that x2=14+65x^2 = 14 + 6\sqrt{5}x2=14+65.
Hence show that x2−6x+4=0x^2 - 6x + 4 = 0x2−6x+4=0.
Hence, or otherwise, find the exact value of x+4xx + \dfrac{4}{x}x+x4.