2.36 g of trimethylamine gas, (CH3)3N(\text{CH}_3)_3\text{N}(CH3)3N (Mr=59.0M_{\text{r}} = 59.0Mr=59.0), is reacted with 80 cm3 of 0.75 mol dm-3 hydrobromic acid forming a solution of trimethylammonium bromide.
(CH3)3N(g)+HBr(aq)→(CH3)3NH+(aq)+Br−(aq) (\text{CH}_3)_3\text{N}(\text{g}) + \text{HBr}(\text{aq}) \rightarrow (\text{CH}_3)_3\text{NH}^+(\text{aq}) + \text{Br}^-(\text{aq}) (CH3)3N(g)+HBr(aq)→(CH3)3NH+(aq)+Br−(aq)What is the concentration of trimethylammonium bromide in mol dm−3\text{mol dm}^{-3}mol dm−3?
0.040.040.04
0.250.250.25
0.500.500.50
0.750.750.75
