How many electrons are removed from 1.35 × 10-2 g of Al(g)\text{Al(g)}Al(g) atoms to form Al3+(g)\text{Al}^{3+}\text{(g)}Al3+(g) ions?
(Avogadro's constant, NA=6.02×1023 mol−1N_A = 6.02 \times 10^{23}\text{ mol}^{-1}NA=6.02×1023 mol−1)
1.00×10201.00 \times 10^{20}1.00×1020
3.01×10203.01 \times 10^{20}3.01×1020
9.03×10209.03 \times 10^{20}9.03×1020
3.91×10213.91 \times 10^{21}3.91×1021
