Complete combustion of 1.20 g of a hydrocarbon yields 1.80 g of water (H2O\text{H}_2\text{O}H2O). What is the empirical formula of the hydrocarbon?
CH2\text{CH}_2CH2
C5H12\text{C}_5\text{H}_{12}C5H12
C3H8\text{C}_3\text{H}_8C3H8
C5H10\text{C}_5\text{H}_{10}C5H10