Propan-1-ol can be prepared by different reactions. Which reaction has the lowest atom economy?
C3H6+H2O→C3H7OH\text{C}_3\text{H}_6 + \text{H}_2\text{O} \rightarrow \text{C}_3\text{H}_7\text{OH}C3H6+H2O→C3H7OH
CH3COOC3H7+H2O→C3H7OH+CH3COOH\text{CH}_3\text{COOC}_3\text{H}_7 + \text{H}_2\text{O} \rightarrow \text{C}_3\text{H}_7\text{OH} + \text{CH}_3\text{COOH}CH3COOC3H7+H2O→C3H7OH+CH3COOH
C3H7Br+NaOH→C3H7OH+NaBr\text{C}_3\text{H}_7\text{Br} + \text{NaOH} \rightarrow \text{C}_3\text{H}_7\text{OH} + \text{NaBr}C3H7Br+NaOH→C3H7OH+NaBr
C3H7Cl+NaOH→C3H7OH+NaCl\text{C}_3\text{H}_7\text{Cl} + \text{NaOH} \rightarrow \text{C}_3\text{H}_7\text{OH} + \text{NaCl}C3H7Cl+NaOH→C3H7OH+NaCl