A student reacts 6.10 g of C6H5COOH\text{C}_6\text{H}_5\text{COOH}C6H5COOH with excess CH3OH\text{CH}_3\text{OH}CH3OH in the reaction below.
C6H5COOH+CH3OH→C6H5COOCH3+H2O \text{C}_6\text{H}_5\text{COOH} + \text{CH}_3\text{OH} \rightarrow \text{C}_6\text{H}_5\text{COOCH}_3 + \text{H}_2\text{O} C6H5COOH+CH3OH→C6H5COOCH3+H2O Mr(C6H5COOH)=122.0Mr(C6H5COOCH3)=136.0 M_{\text{r}}(\text{C}_6\text{H}_5\text{COOH}) = 122.0 \qquad M_{\text{r}}(\text{C}_6\text{H}_5\text{COOCH}_3) = 136.0 Mr(C6H5COOH)=122.0Mr(C6H5COOCH3)=136.0The reaction produces 4.42 g of C6H5COOCH3\text{C}_6\text{H}_5\text{COOCH}_3C6H5COOCH3.
What is the percentage yield of C6H5COOCH3\text{C}_6\text{H}_5\text{COOCH}_3C6H5COOCH3?
54.7
65.0
72.5
80.8