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Amount of substance

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Question 71

A student reacts 6.10 g of C6H5COOH\text{C}_6\text{H}_5\text{COOH}C6​H5​COOH with excess CH3OH\text{CH}_3\text{OH}CH3​OH in the reaction below.

C6H5COOH+CH3OH→C6H5COOCH3+H2O \text{C}_6\text{H}_5\text{COOH} + \text{CH}_3\text{OH} \rightarrow \text{C}_6\text{H}_5\text{COOCH}_3 + \text{H}_2\text{O} C6​H5​COOH+CH3​OH→C6​H5​COOCH3​+H2​O Mr(C6H5COOH)=122.0Mr(C6H5COOCH3)=136.0 M_{\text{r}}(\text{C}_6\text{H}_5\text{COOH}) = 122.0 \qquad M_{\text{r}}(\text{C}_6\text{H}_5\text{COOCH}_3) = 136.0 Mr​(C6​H5​COOH)=122.0Mr​(C6​H5​COOCH3​)=136.0

The reaction produces 4.42 g of C6H5COOCH3\text{C}_6\text{H}_5\text{COOCH}_3C6​H5​COOCH3​.

What is the percentage yield of C6H5COOCH3\text{C}_6\text{H}_5\text{COOCH}_3C6​H5​COOCH3​?

54.7

65.0

72.5

80.8

Amount of substance Questions

  1. A Level
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