0.93 g of methylamine gas, CH3NH2\text{CH}_3\text{NH}_2CH3NH2 (Mr=31.0M_{\text{r}} = 31.0Mr=31.0), is reacted with 50 cm3 of 1.0 mol dm-3 hydrochloric acid forming a solution of methylammonium chloride.
CH3NH2(g)+HCl(aq)→CH3NH3+(aq)+Cl−(aq) \text{CH}_3\text{NH}_2\text{(g)} + \text{HCl(aq)} \rightarrow \text{CH}_3\text{NH}_3^+\text{(aq)} + \text{Cl}^-\text{(aq)} CH3NH2(g)+HCl(aq)→CH3NH3+(aq)+Cl−(aq)What is the concentration of methylammonium chloride in mol dm−3\text{mol dm}^{-3}mol dm−3?
0.03
0.97
0.60
1.00
