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1.7 Energy, work and power

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Question 42

A ball is thrown vertically upwards at a speed of 6.0 m/s.

All of the energy initially in the kinetic store of the ball is transferred to its gravitational potential store when the ball reaches its maximum height.

Taking the gravitational field strength and acceleration due to gravity to be 9.8 m/s2, which equation gives the maximum height h h\,h reached by the ball?

A

h=9.82×6.02h = \frac{9.8}{2 \times 6.0^2}h=2×6.029.8​

B

h=6.02×29.8h = \frac{6.0^2 \times 2}{9.8}h=9.86.02×2​

C

h=6.022×9.8h = \frac{6.0^2}{2 \times 9.8}h=2×9.86.02​

D

h=2×9.86.02h = \frac{2 \times 9.8}{6.0^2}h=6.022×9.8​

Markscheme

1.7 Energy, work and power Questions

  1. IGCSE
  2. /Physics
  3. /1.7 Energy, work and power

533 exam-style questions on CIE IGCSE Physics 1.7 Energy, work and power, covering 1.7.1a Energy stores and energy transfers, 1.7.1b Conservation of energy, 1.7.1c Kinetic and gravitational potential energy, 1.7.2 Work done, 1.7.3 Energy resources, 1.7.3a Energy resources and electricity generation, 1.7.3b Nuclear fusion as an energy source, 1.7.3c Efficiency of energy transfer, and 1.7.4 Power. Each one has a worked solution and a mark scheme showing where the marks go.

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