Prove algebraically, giving your answer in its simplest form, that the recurring decimal 0.3˙7˙8˙0.\dot{3}\dot{7}\dot{8}0.3˙7˙8˙ can be written as 1437\displaystyle \frac{14}{37}3714
203 exam-style questions on Eduqas GCSE Maths Recurring Decimals to Fractions. Each one has a worked solution and a mark scheme showing where the marks go.