k k\,k is an integer such that 1≤k≤9 1 \leq k \leq 9\,1≤k≤9
Prove that 0.k˙0˙=10k99\displaystyle 0.\dot{k}\dot{0} = \frac{10k}{99}0.k˙0˙=9910k
203 exam-style questions on Eduqas GCSE Maths Recurring Decimals to Fractions. Each one has a worked solution and a mark scheme showing where the marks go.