Prove algebraically that the recurring decimal 0.1˙2˙6˙0.\dot{1}\dot{2}\dot{6}0.1˙2˙6˙ can be written as 14111\displaystyle \frac{14}{111}11114 and hence find the value of 0.1˙2˙6˙+0.0˙0˙1˙0.\dot{1}\dot{2}\dot{6} + 0.\dot{0}\dot{0}\dot{1}0.1˙2˙6˙+0.0˙0˙1˙
203 exam-style questions on Eduqas GCSE Maths Recurring Decimals to Fractions. Each one has a worked solution and a mark scheme showing where the marks go.