Prove algebraically that the recurring decimal 0.23˙0.2\dot{3}0.23˙ can be written as 730\displaystyle \frac{7}{30}307
Hence, work out 0.23˙+13\displaystyle 0.2\dot{3}+\frac{1}{3}0.23˙+31
203 exam-style questions on Eduqas GCSE Maths Recurring Decimals to Fractions. Each one has a worked solution and a mark scheme showing where the marks go.