Prove algebraically that the recurring decimal 0.2˙1˙6˙0.\dot{2}\dot{1}\dot{6}0.2˙1˙6˙ can be written as 837\displaystyle \frac{8}{37}378 and hence find the value of 0.2˙1˙6˙+137\displaystyle 0.\dot{2}\dot{1}\dot{6}+\frac{1}{37}0.2˙1˙6˙+371
203 exam-style questions on Eduqas GCSE Maths Recurring Decimals to Fractions. Each one has a worked solution and a mark scheme showing where the marks go.