Prove algebraically that the recurring decimal 0.0˙3˙7˙0.\dot{0}\dot{3}\dot{7}0.0˙3˙7˙ can be written as 127\displaystyle \frac{1}{27}271
203 exam-style questions on Eduqas GCSE Maths Recurring Decimals to Fractions. Each one has a worked solution and a mark scheme showing where the marks go.